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globals[ all-colors colors-dissemination all-labels labels-dissemination individualists n ] turtles-own[ nei individualist? updates ] to setup ca set-patch-size (760 / world-size ) resize-world 0 (world-size - 1) 0 (world-size - 1) if set-random-seed? [random-seed random-seed-number] ;; setting the list with all possible colors set all-colors [5 15 25 35 45 55 65 75 85 95 105 115 125 135] let x all-colors let y  ;; preparing list Y with starting set of colors; LENGTH of Y equals to slider variable INITIAL-COLORS repeat initial-colors[ let z random (length x) set y lput (item z x) y set x remove-item z x ] set all-labels [0 1 2 3 4 5 6 7 8 9 10 11 12 13] let xx all-labels let yy  ;; preparing list YY with starting set of labels; LENGTH of YY equals to slider variable INITIAL-LABELS repeat initial-labels[ let z random (length xx) set yy lput (item z xx) yy set xx remove-item z xx ] ;; give a birth to agents through patches let nn (agents-density * world-size * world-size / 100) ask n-of nn patches[ sprout 1[ set color one-of y set label one-of yy ifelse (random-float 1) < individualist-chance [set individualist? true] [set individualist? false] ] ] ask turtles[ ifelse random-radius? [set nei turtles in-radius (1 + random-float (nei-radius - 0.9))] [set nei turtles in-radius nei-radius] ] ;; setting list COLORS-DISSEMINATION monitor-dissemintion ;; set number of individualists for monitoring purposes set individualists count turtles with [individualist? = true] ;; set number of all turtles as N set n count turtles reset-ticks end to go ;; HOW WILL THE PROCESS OF BLAHA'S SOCIAL FUNCTION WORK? ;; 1] in one turn we randomly pick up one neigrborhood ;; 2] we check the color homogeneity of neighborhood ;; 3] in case it is not homogenous, we find style with smallest overall effort needed for change ;; // alternatively: we find modus ;; 4] style is picked out from list of neighbors styles, the individualists put new styles on the list, as well ;; 5] all neighborhood adopts the effortless style ;; (effortless = the least sum of distances from present style of turtle and the style on the list) ;; 6] tick, go to  ;; ad  ask one-of turtles[ ;ask turtles[ ;; firstly, we update individualists ad  ask nei with [individualist?][ ;; version where individualists take one of possible solution regardless it is alternative or not: if individualist-change > random-float 1 [set color (one-of all-colors)] if individualist-change > random-float 1 [set label (one-of all-labels)] ] ;; preparing for ad  let x [color] of nei ;; ad  if (max x) != (min x)[ ;; ad  let unified-color 0 if mechanism = "1=effortless" [set unified-color effortless-style (nei) (x)] if mechanism = "2=modus" [set unified-color modes-style (nei) (x)] if mechanism = "3=randomMix" [ ifelse random 2 = 1 [set unified-color effortless-style (nei) (x)] [set unified-color modes-style (nei) (x)] ] ;; ad  ask nei[ set color unified-color set updates (updates + 1) ] ] ;; preparing for ad  and ad  let xx [label] of nei if (max xx) != (min xx)[ ;; ad  let unified-label -1 if mechanism = "1=effortless" [set unified-label effortless-style (nei) (xx)] if mechanism = "2=modus" [set unified-label modes-style (nei) (xx)] if mechanism = "3=randomMix" [ ifelse random 2 = 1 [set unified-label effortless-style (nei) (xx)] [set unified-label modes-style (nei) (xx)] ] ;; ad  ask nei[ set label unified-label set updates (updates + 1) ] ] ] ;; ad  tick ;; checking whether one color dominates all turtles monitor-dissemintion if ending? [stop] if minimal-updates? [if min [updates] of turtles > minimal-updates [stop]] end to monitor-dissemintion set colors-dissemination  foreach all-colors[ set colors-dissemination lput (count turtles with [color = ?]) colors-dissemination ] set labels-dissemination  foreach all-labels[ set labels-dissemination lput (count turtles with [label = ?]) labels-dissemination ] end ;; ad  and ad  to-report modes-style [y xList] ;; Y is agentset NEI ;; USED COLORS/LABELS: presently used colors/labels in neighborhood are recorded in xList ;; now, we report the modus - in case we have more than 1 mode, we choose on of them randomly report one-of modes xList end ;; ad  and ad  to-report effortless-style [y xList] ;; Y is agentset NEI ;; xList is new and old values used inside NEI ;; for checking effortless value, we need to copy original eList to yList let yList xList ;; now we need to reduce the xList only to unique values set xList remove-duplicates xList ;; counting effort of whole NEI in case of changing COLOR/LABEL to every value from xList ;; no other than xList could be used, because Blaha said that all values should be lived and let effort  foreach xList[ ;; Z is effort needed for change to respective color/label from the xList let xx ? let zList  foreach yList [set zList lput xx zList] let z 0 (foreach yList zList [set z z + abs(?1 - ?2)]) set effort lput z effort ] ;; now we find the position of minimal effort and doing so we find the effortless color let p position (min effort) effort report item p xList end to-report ending? ;; value of ENDING? will be TRUE when all turtles will have same color, ;; it means that for one color will hold TRUE that number of tortles of this color equals to number of all turtles ;; for all the other colors it will hold FALSE ;; initializing list M where we will save logical value whether respective color is used by all turtles let m  ;; rolling over list M and saving logical values whether respective colors are used by all turtles ;; number of all turtles is set at setup phase as N foreach all-colors[ set m lput (n = count turtles with [color = ?]) m ] ;; reducing list M, we are only interested in whether all values are FALSE, or one value of them is TRUE set m remove-duplicates m ;; we know that only one color could be TRUE, it means used by all turtles, in that case LENGTH of lis M is 2 ;; otherwise list M consists of only FALSE values and after reduction its LENGTH equals to 1 ;report length m = 2 ;; so, in case one color is used by all turtles LENGTH of list M is 2 and procedure ENDING? reports value TRUE ;; now we have 2 traits, so we also prepare list MM for the labels and do the same for labels let mm  foreach all-labels[ set mm lput (n = count turtles with [label = ?]) mm ] set mm remove-duplicates mm ;; now we reports the both traits are same, it means we sum length of both lists and check the sum against number 4, ;; which means value TRUE is on the both lists report (length m + length mm) = 4 end