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globals[ all-colors colors-dissemination individualists available-colors available-distances ] turtles-own[ nei individualist? updates peak disposition original-color ] to setup ca set-patch-size (760 / world-size ) resize-world 0 (world-size - 1) 0 (world-size - 1) if set-random-seed? [random-seed random-seed-number] ;; setting the list with all possible colors set all-colors [5 15 25 35 45 55 65 75 85 95 105 115 125 135] let x all-colors let y  ;; preparing list Y with starting set of colors; LENGTH of Y equals to slider variable INITIAL-COLORS repeat initial-colors[ let z random (length x) set y lput (item z x) y set x remove-item z x ] let n (agents-density * world-size * world-size / 100) ask n-of n patches[ sprout 1[ ;; set DISPOSITION - needed for [4b] set-disposition ;; secondly, we randomly assign the color set color one-of y ;; thirdly, we check whether the agent is able to live the assigned value let xx position color all-colors let yy item xx disposition if yy > 1 [ ;; now, we know that the asigned value is not possible for living ;; so, we have to try other values of Y, whether they are possible for living let zz y set zz remove color zz while [length zz > 0 and yy > 1] [ set color one-of zz set zz remove color zz set xx position color all-colors set yy item xx disposition ] ] ;; but it is possible that the agent is able to live no value of Y ;; so, we randomly assign any value which the agent is able to live while [yy > 1] [ set color one-of all-colors set xx position color all-colors set yy item xx disposition ] ;; lastly, we set whether the agent is INDIVIDUALIST? or not ifelse (random-float 1) < individualist-chance [set individualist? true] [set individualist? false] ] ] ask turtles[ ifelse random-radius? [set nei turtles in-radius (1 + random-float (nei-radius - 0.9))] [set nei turtles in-radius nei-radius] ] ;; setting list COLORS-DISSEMINATION monitor-dissemintion set individualists count turtles with [individualist? = true] reset-ticks end to go ;; HOW WILL THE PROCESS OF BLAHA'S SOCIAL FUNCTION WORK? ;; 1] in one turn we randomly pick up one neigrborhood ;; 2] we check the color homogeneity of neighborhood, BUT also whether there are some individualists ;; 3] in case it is not homogenous, we find style with smallest overall effort needed for change ;; 4] style is picked out from list of neighbors styles, the individualists put new styles on the list, as well ;; 4b] distance of styles is weighted by DISPOSITION ;; 4c] agents are not able to live the agreed value everytime ;; 5] all neighborhood adopts the effortless style ;; (effortless = the least sum of distances from present style of turtle and the style on the list) ;; 6] tick, go to  ;; ad  ask one-of turtles[ ;ask turtles[ ;; just for the orientation, we change color of the black patches to the white ask nei [ask patch-here [set pcolor white]] ;; first of all, we save the original color before all other ask nei [set original-color color] ;; preparing for ad  and ad  let x [color] of nei let i [individualist?] of nei ;; preparing ad  - actively used colors in the neighborhood AND ad  number of individualists set x remove-duplicates x set i remove false i ;; ad  if length x > 1 or length i > 0[ ;; ad  let unified-color effortless-style (x) (nei) ;; ad  ask nei[ set color unified-color ;; but some agents are not able to live the consensus represented by UNIFIED-COLOR ;; they change to one of AVAILABLE-COLORS which is both liveable value for the agent closest to the consensus ;; so, now we have to find it! ;; ;; here we find the position of agreed color/value let xx position color all-colors ;; here we take a DISPOSITION on the same position let yy item xx disposition ;; now we have to copy AVAILABLE-COLORS and AVAILABLE-DISTANCES let zz1 available-colors let zz2 available-distances ;; now we take a position of the agreed color/value and distances of AVAILABLE-COLORS to it on ZZ1 and ZZ2 let xxx position color available-colors ;; now we remove agreed color/value from the ZZ1 and ZZ2 set zz1 remove-item xxx zz1 set zz2 remove-item xxx zz2 while [yy > 1 and length zz1 > 0] [ ;; now we find position PP of the color with the minimal distance to the agreed color/value let pp position (min zz2) zz2 ;; now we set color of the agent to the AVAILABLE-COLOR closest to the agreed color/value set color item pp zz1 ;; now we have to remove color from the color lis and distance from the distance list set zz1 remove-item pp zz1 set zz2 remove-item pp zz2 ;; now we find out whether the taken value/color is liveable set xx position color all-colors set yy item xx disposition ] if yy > 1 [set color original-color] set updates (updates + 1) ] ] ] ;; ad  tick ;; checking whether one color dominates all turtles monitor-dissemintion if ending? [stop] if minimal-updates? [if min [updates] of turtles > minimal-updates [stop]] ask patches with [pcolor = white] [set pcolor black] end to set-disposition ;; firstly, I have to chose the PEAK (the best lived value) ;; the problem is, how to chose value randomly - as a flat, random normal, or other distribution set peak -1 if peak-disposition-distribution = "flat" [set peak random-float 140] if peak-disposition-distribution = "random normal" [ while [peak < 0 or peak > 140] [set peak random-normal 70 33] ] ;;secondly, we could assign weights of values to DISPOSITION according random distribution set disposition  foreach all-colors[ ;;a1=random value between 0 and 140 ;;a2=one of the all-colors values [5 15 25 35 45 55 65 75 85 95 105 115 125 135] ;;b2=(A2*4/140)-($A$1/35) ;;c2=2-(EXP(-(((B2)^2)/2)))*2 let z1 (4 * ? / 140) - (peak / 35) let z2 maximum-weight - (exp(0 - ((z1 ^ 2) / 2)) * maximum-weight) set z2 precision z2 2 set disposition lput z2 disposition ] ;;print disposition end to monitor-dissemintion set colors-dissemination  foreach all-colors[ set colors-dissemination lput (count turtles with [color = ?]) colors-dissemination ] end ;; ad  and ad  to-report effortless-style [x y] ;; finding of new colors by individualists inside nei let using-colors x ask y with [individualist?][ ;; version where individualists take one of possible solution regardless it is alternative or not: set color (one-of all-colors) let xx position color all-colors let yy item xx disposition while [yy > 1] [ set color one-of all-colors set xx position color all-colors set yy item xx disposition ] set using-colors lput color using-colors ;; now, the individualist just has changed his color to the new original one, so we have to rewrite his/her ORIGINAL-COLOR by the lived color/value set original-color color ] set using-colors remove-duplicates using-colors set using-colors sort using-colors ;; counting effort of whole NEI in case of changing COLOR to every value from USING-COLORS ;; no other than USING-COLORS could be used, because Blaha said that all values should be lived and ;; only individuals are able to live value which is not present in the NEI (we take it that they ;; "invent" new value and immediately they live it and through this they present it to others in NEI) let effort  foreach using-colors[ ;; Z is effort needed for change to respective color from the USING-COLORS let z 0 ask y[ ;; we find the WEIGHT/DISPOSITION of respective value/color let xxx position ? all-colors let weight item xxx disposition ;; now, we can compute the EFFORT Z set z z + (weight * abs(color - ?)) ] set effort lput z effort ] ;; now we find the position of minimal effort and doing so we find the effortless color let p position (min effort) effort ;; we also save USING-COLORS to AVAILABLE-COLORS, i.e. all colors/values used ;; during the discussion will be available for the later use in case the agreement will not be liveable for an agent set available-colors using-colors ;; paralelly, we also save distances of AVAILABLE-COLORS let agreement item p using-colors set available-distances  foreach using-colors [ ;; note: because list operations take the first item in the case of tie and we want to ;; bring some randomness to the process of selection, so we add to the distance [RANDOM-FLOAT 1]; ;; it is minimal noise, because distances are 0, 10, 20, 30 etc. to the 130, ;; it is never e.g. 35, 26, 17 etc. set available-distances lput (abs(agreement - ?) + (precision random-float 1 3)) available-distances ] report item p using-colors end to-report ending? ;; value of ENDING? will be TRUE when all turtles will have same color, ;; it means that for one color will hold TRUE that number of tortles of this color equals to number of all turtles ;; for all the other colors it will hold FALSE ;; set number of all turtles as N let n count turtles ;; initializing list M where we will save logical value whether respective color is used by all turtles let m  ;; rolling over list M and saving logical values whether respective colors are used by all turtles foreach all-colors[ set m lput (n = count turtles with [color = ?]) m ] ;; reducing list M, we are only interested in whether all values are FALSE, or one value of them is TRUE set m remove-duplicates m ;print m ;; we know that only one color could be TRUE, it means used by all turtles, in that case LENGTH of lis M is 2 ;; otherwise list M consists of only FALSE values and after reduction its LENGTH equals to 1 report length m = 2 ;; so, in case one color is used by all turtles LENGTH of list M is 2 and procedure ENDING? reports value TRUE end