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view/download model file: BlahaV02.nlogo


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to setup
  set-patch-size (760 / world-size )
  resize-world 0 (world-size - 1) 0 (world-size - 1)
  if set-random-seed? [random-seed random-seed-number]
  ;; setting the list with all possible colors
  set all-colors [5 15 25 35 45 55 65 75 85 95 105 115 125 135]
  let x all-colors
  let y []
  ;; preparing list Y with starting set of colors; LENGTH of Y equals to slider variable INITIAL-COLORS
  repeat initial-colors[
    let z random (length x) 
    set y lput (item z x) y
    set x remove-item z x
  let n (agents-density * world-size * world-size  / 100)
  ask n-of n patches[
    sprout 1[
      ;; set DISPOSITION - needed for [4b]
      ;; secondly, we randomly assign the color
      set color one-of y
      ;; thirdly, we check whether the agent is able to live the assigned value
      let xx position color all-colors
      let yy item xx disposition
      if yy > 1 [ 
        ;; now, we know that the asigned value is not possible for living
        ;; so, we have to try other values of Y, whether they are possible for living
        let zz y
        set zz remove color zz
        while [length zz > 0 and yy > 1] [
          set color one-of zz
          set zz remove color zz
          set xx position color all-colors
          set yy item xx disposition
      ;; but it is possible that the agent is able to live no value of Y
      ;; so, we randomly assign any value which the agent is able to live          
      while [yy > 1] [
          set color one-of all-colors
          set xx position color all-colors
          set yy item xx disposition
      ;; lastly, we set whether the agent is INDIVIDUALIST? or not
      ifelse (random-float 1) < individualist-chance [set individualist? true] [set individualist? false]
  ask turtles[
    ifelse random-radius?
    [set nei turtles in-radius (1 + random-float (nei-radius - 0.9))]
    [set nei turtles in-radius nei-radius]
  ;; setting list COLORS-DISSEMINATION
  set individualists count turtles with [individualist? = true]

to go
  ;; 1] in one turn we randomly pick up one neigrborhood
  ;; 2] we check the color homogeneity of neighborhood, BUT also whether there are some individualists
  ;; 3] in case it is not homogenous, we find style with smallest overall effort needed for change
  ;; 4] style is picked out from list of neighbors styles, the individualists put new styles on the list, as well
  ;; 4b] distance of styles is weighted by DISPOSITION
  ;; 4c] agents are not able to live the agreed value everytime
  ;; 5] all neighborhood adopts the effortless style
  ;; (effortless = the least sum of distances from present style of turtle and the style on the list)
  ;; 6] tick, go to [1]
  ;; ad [1]
  ask one-of turtles[
  ;ask turtles[
    ;; just for the orientation, we change color of the black patches to the white
    ask nei [ask patch-here [set pcolor white]]    
    ;; first of all, we save the original color before all other
    ask nei [set original-color color]
    ;; preparing for ad [2] and ad [4]
    let x [color] of nei
    let i [individualist?] of nei
    ;; preparing ad [4] - actively used colors in the neighborhood AND ad [2] number of individualists
    set x remove-duplicates x
    set i remove false i
    ;; ad [2]
    if length x > 1 or length i > 0[
      ;; ad [3]
      let unified-color effortless-style (x) (nei)
      ;; ad [5]
      ask nei[
        set color unified-color
        ;; but some agents are not able to live the consensus represented by UNIFIED-COLOR
        ;; they change to one of AVAILABLE-COLORS which is both liveable value for the agent closest to the consensus
        ;; so, now we have to find it!
        ;; here we find the position of agreed color/value
        let xx position color all-colors
        ;; here we take a DISPOSITION on the same position
        let yy item xx disposition
        ;; now we have to copy AVAILABLE-COLORS and AVAILABLE-DISTANCES
        let zz1 available-colors
        let zz2 available-distances
        ;; now we take a position of the agreed color/value and distances of AVAILABLE-COLORS to it on ZZ1 and ZZ2
        let xxx position color available-colors
        ;; now we remove agreed color/value from the ZZ1 and ZZ2
        set zz1 remove-item xxx zz1
        set zz2 remove-item xxx zz2
        while [yy > 1 and length zz1 > 0] [
          ;; now we find position PP of the color with the minimal distance to the agreed color/value
          let pp position (min zz2) zz2
          ;; now we set color of the agent to the AVAILABLE-COLOR closest to the agreed color/value
          set color item pp zz1
          ;; now we have to remove color from the color lis and distance from the distance list
          set zz1 remove-item pp zz1
          set zz2 remove-item pp zz2
          ;; now we find out whether the taken value/color is liveable
          set xx position color all-colors
          set yy item xx disposition
        if yy > 1 [set color original-color]
        set updates (updates + 1)
  ;; ad [6]
  ;; checking whether one color dominates all turtles
  if ending? [stop]
  if minimal-updates? [if min [updates] of turtles > minimal-updates [stop]]
  ask patches with [pcolor = white] [set pcolor black]

to set-disposition
  ;; firstly, I have to chose the PEAK (the best lived value)
  ;; the problem is, how to chose value randomly  - as a flat, random normal, or other distribution 
  set peak -1
  if peak-disposition-distribution = "flat" [set peak random-float 140]
  if peak-disposition-distribution = "random normal" [
    while [peak < 0 or peak > 140] [set peak random-normal 70 33]
  ;;secondly, we could assign weights of values to DISPOSITION according random distribution
  set disposition []
  foreach all-colors[
    ;;a1=random value between 0 and 140
    ;;a2=one of the all-colors values [5 15 25 35 45 55 65 75 85 95 105 115 125 135]
    let z1 (4 * ? / 140) - (peak / 35)
    let z2 maximum-weight - (exp(0 - ((z1 ^ 2) / 2)) * maximum-weight)
    set z2 precision z2 2
    set disposition lput z2 disposition
  ;;print disposition

to monitor-dissemintion
  set colors-dissemination []
  foreach all-colors[
    set colors-dissemination lput (count turtles with [color = ?]) colors-dissemination

;; ad [3] and ad [4]
to-report effortless-style [x y]
  ;; finding of new colors by individualists inside nei
  let using-colors x
  ask y with [individualist?][
    ;; version where individualists take one of possible solution regardless it is alternative or not:
    set color (one-of all-colors)
    let xx position color all-colors
    let yy item xx disposition
    while [yy > 1] [
       set color one-of all-colors
       set xx position color all-colors
       set yy item xx disposition
    set using-colors lput color using-colors
    ;; now, the individualist just has changed his color to the new original one, so we have to rewrite his/her ORIGINAL-COLOR by the lived color/value
    set original-color color
  set using-colors remove-duplicates using-colors
  set using-colors sort using-colors
  ;; counting effort of whole NEI in case of changing COLOR to every value from USING-COLORS
  ;; no other than USING-COLORS could be used, because Blaha said that all values should be lived and
  ;; only individuals are able to live value which is not present in the NEI (we take it that they 
  ;; "invent" new value and immediately they live it and through this they present it to others in NEI)
  let effort []
  foreach using-colors[
    ;; Z is effort needed for change to respective color from the USING-COLORS
    let z 0
    ask y[
      ;; we find the WEIGHT/DISPOSITION of respective value/color
      let xxx position ? all-colors
      let weight item xxx disposition
      ;; now, we can compute the EFFORT Z
      set z z + (weight * abs(color - ?))
    set effort lput z effort
  ;; now we find the position of minimal effort and doing so we find the effortless color
  let p position (min effort) effort
  ;; we also save USING-COLORS to AVAILABLE-COLORS, i.e. all colors/values used 
  ;; during the discussion will be available for the later use in case the agreement will not be liveable for an agent
  set available-colors using-colors
  ;; paralelly, we also save distances of AVAILABLE-COLORS
  let agreement item p using-colors
  set available-distances []
  foreach using-colors [
    ;; note: because list operations take the first item in the case of tie and we want to
    ;; bring some randomness to the process of selection, so we add to the distance [RANDOM-FLOAT 1];
    ;; it is minimal noise, because distances are 0, 10, 20, 30 etc. to the 130, 
    ;; it is never e.g. 35, 26, 17 etc.
    set available-distances lput (abs(agreement - ?) + (precision random-float 1 3)) available-distances 
  report item p using-colors

to-report ending?
  ;; value of ENDING? will be TRUE when all turtles will have same color,
  ;; it means that for one color will hold TRUE that number of tortles of this color equals to number of all turtles
  ;; for all the other colors it will hold FALSE 
  ;; set number of all turtles as N
  let n count turtles
  ;; initializing list M where we will save logical value whether respective color is used by all turtles
  let m []
  ;; rolling over list M and saving logical values whether respective colors are used by all turtles
  foreach all-colors[
    set m lput (n = count turtles with [color = ?]) m
  ;; reducing list M, we are only interested in whether all values are FALSE, or one value of them is TRUE
  set m remove-duplicates m
  ;print m
  ;; we know that only one color could be TRUE, it means used by all turtles, in that case LENGTH of lis M is 2
  ;; otherwise list M consists of only FALSE values and after reduction its LENGTH equals to 1
  report length m = 2
  ;; so, in case one color is used by all turtles LENGTH of list M is 2 and procedure ENDING? reports value TRUE